(x+2)^2=(x+2)(5x-4)

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Solution for (x+2)^2=(x+2)(5x-4) equation: 



(x+2)^2=(x+2)(5x-4)

We move all terms to the left:

(x+2)^2-((x+2)(5x-4))=0

We multiply parentheses ..

-((+5x^2-4x+10x-8))+(x+2)^2=0



We calculate terms in parentheses: -((+5x^2-4x+10x-8)), so:

(+5x^2-4x+10x-8)

We get rid of parentheses

5x^2-4x+10x-8

We add all the numbers together, and all the variables

5x^2+6x-8

Back to the equation:

-(5x^2+6x-8)



We get rid of parentheses

-5x^2-6x+(x+2)^2+8=0

We move all terms containing x to the left, all other terms to the right

-5x^2-6x+(x+2)^2=-8

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